C program to Find all Roots of a Quadratic equation

This program accepts coefficients of a quadratic equation from the user and displays the roots (both real and complex roots depending upon the determinant).

To understand this example, you should have the knowledge of following C programming topics:

Quadratic equation graph

The standard form of a quadratic equation is:

ax2 + bx + c = 0, where
a, b and c are real numbers and
a ≠ 0

The term b2-4ac is known as the determinant of a quadratic equation. The determinant tells the nature of the roots.

  • If the determinant is greater than 0, the roots are real and different.
  • If the determinant is equal to 0, the roots are real and equal.
  • If the determinant is less than 0, the roots are complex and different.

Calculation of roots of a quadratic equation

Example: Program to Find Roots of a Quadratic Equation

#include <stdio.h>
#include <math.h>

int main()
    double a, b, c, determinant, root1,root2, realPart, imaginaryPart;

    printf("Enter coefficients a, b and c: ");
    scanf("%lf %lf %lf",&a, &b, &c);

    determinant = b*b-4*a*c;

    // condition for real and different roots
    if (determinant > 0)
    // sqrt() function returns square root
        root1 = (-b+sqrt(determinant))/(2*a);
        root2 = (-b-sqrt(determinant))/(2*a);

        printf("root1 = %.2lf and root2 = %.2lf",root1 , root2);

    //condition for real and equal roots
    else if (determinant == 0)
        root1 = root2 = -b/(2*a);

        printf("root1 = root2 = %.2lf;", root1);

    // If roots is not 
        realPart = -b/(2*a);
        imaginaryPart = sqrt(-determinant)/(2*a);
        printf("root1 = %.2lf+%.2lfi and root2 = %.2f-%.2fi", realPart, imaginaryPart, realPart, imaginaryPart);

    return 0;


Enter coefficients a, b and c: 2.3
Roots are: -0.87+1.30i and -0.87-1.30i

In this program, library function sqrt() is used to find the square root of a number. To learn more, visit:  sqrt() function.