Arrays are closely related to pointers in C programming but the important difference between them is that, a pointer variable can take different addresses as value whereas, in case of array it is fixed. This can be demonstrated by an example:

```
#include <stdio.h>
int main(){
char c[4];
int i;
for(i=0;i<4;++i){
printf("Address of c[%d]=%x\n",i,&c[i]);
}
return 0;
}
```

`Address of c[0]=28ff44
Address of c[1]=28ff45
Address of c[2]=28ff46
Address of c[3]=28ff47`

Notice, that there is equal difference (difference of 1 byte) between any two consecutive elements of array.

**Note:** You may get different address of an array.

## Relation between Arrays and Pointers

Consider and array:

int arr[4];

In arrays of C programming, name of the array always points to the first element of an array. Here, address of first element of an array is `&arr[0]`

. Also, `arr` represents the address of the pointer where it is pointing. Hence, `&arr[0] is equivalent to `

`arr`.

Also, value inside the address `&arr[0]`

and address `arr` are equal. Value in address `&arr[0]`

is `arr[0]`

and value in address` arr` is `*arr`

. Hence, `arr[0] is equivalent to *arr`

.

Similarly,

&a[1] is equivalent to (a+1) AND, a[1] is equivalent to *(a+1).
&a[2] is equivalent to (a+2) AND, a[2] is equivalent to *(a+2).
&a[3] is equivalent to (a+1) AND, a[3] is equivalent to *(a+3).
.
.
&a[i] is equivalent to (a+i) AND, a[i] is equivalent to *(a+i).

In C, you can declare an array and can use pointer to alter the data of an array.

```
//Program to find the sum of six numbers with arrays and pointers.
#include <stdio.h>
int main(){
int i,class[6],sum=0;
printf("Enter 6 numbers:\n");
for(i=0;i<6;++i){
scanf("%d",(class+i)); // (class+i) is equivalent to &class[i]
sum += *(class+i); // *(class+i) is equivalent to class[i]
}
printf("Sum=%d",sum);
return 0;
}
```

**Output**

`Enter 6 numbers:
2
3
4
5
3
4
Sum=21`