C Programming switch...case Statement

In this tutorial, you will learn to put a switch statement in C programming with the help of an example.
Switch case in Programming

The nested if...else statement allows you to execute a block code among many alternatives. If you are checking on the value of a single variable in nested if...else statement, it is better to use switch statement.

The switch statement is often faster than nested if...else (not always). Also, the syntax of switch statement is cleaner and easy to understand.

Syntax of switch...case

switch (n)
    case constant1:
        // code to be executed if n is equal to constant1;

    case constant2:
        // code to be executed if n is equal to constant2;
        // code to be executed if n doesn't match any constant

When a case constant is found that matches the switch expression, control of the program passes to the block of code associated with that case.

In the above pseudo code, suppose the value of n is equal to constant2. The compiler will execute the block of code associate with the case statement until the end of switch block, or until the break statement is encountered.

The break statement is used to prevent the code running into the next case.

switch Statement Flowchart

Flowchart of switch statement


Example: switch Statement

// Program to create a simple calculator
// Performs addition, subtraction, multiplication or division depending the input from user

# include <stdio.h>

int main() {

    char operator;
    double firstNumber,secondNumber;

    printf("Enter an operator (+, -, *,): ");
    scanf("%c", &operator);

    printf("Enter two operands: ");
    scanf("%lf %lf",&firstNumber, &secondNumber);

        case '+':
            printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber+secondNumber);

        case '-':
            printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber-secondNumber);

        case '*':
            printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber*secondNumber);

        case '/':
            printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber/firstNumber);

        // operator is doesn't match any case constant (+, -, *, /)
            printf("Error! operator is not correct");

    return 0;


Enter an operator (+, -, *,): -
Enter two operands: 32.5
32.5 - 12.4 = 20.1

The - operator entered by the user is stored in operator variable. And, the two operands, 32.5 and 12.4 are stored in variable firstNumber and secondNumber respectively.

Then, control of the program jumps to

printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber/firstNumber);

Finally, the break; statement ends the switch statement.