## Access Array Elements Using Pointers

```
#include <stdio.h>
int main() {
int data[5];
printf("Enter elements: ");
for (int i = 0; i < 5; ++i)
scanf("%d", data + i);
printf("You entered: \n");
for (int i = 0; i < 5; ++i)
printf("%d\n", *(data + i));
return 0;
}
```

**Output **

Enter elements: 1 2 3 5 4 You entered: 1 2 3 5 4

In this program, the elements are stored in the integer array `data[]`

.

Then, the elements of the array are accessed using the pointer notation. By the way,

`data[0]`

is equivalent to`*data`

and`&data[0]`

is equivalent to`data`

`data[1]`

is equivalent to`*(data + 1)`

and`&data[1]`

is equivalent to`data + 1`

`data[2]`

is equivalent to`*(data + 2)`

and`&data[2]`

is equivalent to`data + 2`

`...`

`data[i]`

is equivalent to`*(data + i)`

and`&data[i]`

is equivalent to`data + i`

Visit this page to learn about the relationship between pointers and arrays.