Join our newsletter for the latest updates.

C Program to Store Information of Students Using Structure

In this example, you will learn to store the information of 5 students by using an array of structures.

To understand this example, you should have the knowledge of the following C programming topics:


Store Information in Structure and Display it

#include <stdio.h>
struct student {
    char firstName[50];
    int roll;
    float marks;
} s[10];

int main() {
    int i;
    printf("Enter information of students:\n");

    // storing information
    for (i = 0; i < 5; ++i) {
        s[i].roll = i + 1;
        printf("\nFor roll number%d,\n", s[i].roll);
        printf("Enter first name: ");
        scanf("%s", s[i].firstName);
        printf("Enter marks: ");
        scanf("%f", &s[i].marks);
    }
    printf("Displaying Information:\n\n");

    // displaying information
    for (i = 0; i < 5; ++i) {
        printf("\nRoll number: %d\n", i + 1);
        printf("First name: ");
        puts(s[i].firstName);
        printf("Marks: %.1f", s[i].marks);
        printf("\n");
    }
    return 0;
}

Output

Enter information of students: 

For roll number1,
Enter name: Tom
Enter marks: 98

For roll number2,
Enter name: Jerry
Enter marks: 89
.
.
.
Displaying Information:

Roll number: 1
Name: Tom
Marks: 98
.
.
.

In this program, a structure student is created. The structure has three members: name (string), roll (integer) and marks (float).

Then, we created an array of structures s having 5 elements to store information of 5 students.

Using a for loop, the program takes the information of 5 students from the user and stores it in the array of structure. Then using another for loop, the information entered by the user is displayed on the screen.

Did you find this article helpful?