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C ispunct()

The ispunct() function checks whether a character is a punctuation mark or not.

The function prototype of ispunct() is:

int ispunct(int argument);

If a character passed to the ispunct() function is a punctuation, it returns a non-zero integer. If not, it returns 0.

In C programming, characters are treated as integers internally. That's why ispunct() takes an integer argument.

The ispunct() function is defined in the ctype.h header file.


Example 1: Program to check punctuation

#include <stdio.h>
#include <ctype.h>

int main() {
   char c;
   int result;

   c = ':';
   result = ispunct(c);

   if (result == 0) {
      printf("%c is not a punctuation", c);
   } else {
      printf("%c is a punctuation", c);
   }

   return 0;
}

Output

: is a punctuation

Example 2: Print all Punctuations

#include <stdio.h>
#include <ctype.h>
int main()
{
    int i;
    printf("All punctuations in C: \n");

    // looping through all ASCII characters
    for (i = 0; i <= 127; ++i)
        if(ispunct(i)!= 0)
            printf("%c ", i);
    return 0;
}

Output

All punctuations in C: 
! " # $ % & ' ( ) * + , - . / : ; < = > ? @ [ \ ] ^ _ ` { | } ~