In this program, you will learn to check whether a year is leap year or not. We will use nested if...else to solve this problem.

To understand this example, you should have the knowledge of following Python programming topics:

A leap year is exactly divisible by 4 except for century years (years ending with 00). The century year is a leap year only if it is perfectly divisible by 400. For example,

2017 is not a leap year 1900 is a not leap year 2012 is a leap year 2000 is a leap year

# Python program to check if the input year is a leap year or not year = 2000 # To get year (integer input) from the user # year = int(input("Enter a year: ")) if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print("{0} is a leap year".format(year)) else: print("{0} is not a leap year".format(year)) else: print("{0} is a leap year".format(year)) else: print("{0} is not a leap year".format(year))

**Output**

2000 is a leap year

You can change the value of `year` in the source code and run it again to test this program.