Python Program to Check Prime Number

To understand this example, you should have the knowledge of the following Python programming topics:


A positive integer greater than 1 which has no other factors except 1 and the number itself is called a prime number. 2, 3, 5, 7 etc. are prime numbers as they do not have any other factors. But 6 is not prime (it is composite) since, 2 x 3 = 6.


Example 1: Using a flag variable

# Program to check if a number is prime or not

num = 29

# To take input from the user
#num = int(input("Enter a number: "))

# define a flag variable
flag = False

if num == 1:
    print(num, "is not a prime number")
elif num > 1:
    # check for factors
    for i in range(2, num):
        if (num % i) == 0:
            # if factor is found, set flag to True
            flag = True
            # break out of loop
            break

    # check if flag is True
    if flag:
        print(num, "is not a prime number")
    else:
        print(num, "is a prime number")

Output

29 is a prime number

In this program, we have checked if num is prime or not. Numbers less than or equal to 1 are not prime numbers. Hence, we only proceed if the num is greater than 1.

We check if num is exactly divisible by any number from 2 to num - 1. If we find a factor in that range, the number is not prime, so we set flag to True and break out of the loop.

Outside the loop, we check if flag is True or False.

  • If it is True, num is not a prime number.
  • If it is False, num is a prime number.

Note: We can improve our program by decreasing the range of numbers where we look for factors.

In the above program, our search range is from 2 to num - 1.

We could have used the range, range(2,num//2) or range(2,math.floor(math.sqrt(num)+1)). The latter range is based on the fact that a composite number must have a factor less than or equal to the square root of that number. Otherwise, the number is prime.

You can change the value of variable num in the above source code to check whether a number is prime or not for other integers.

In Python, we can also use the for...else statement to do this task without using an additional flag variable.


Example 2: Using a for...else statement

num = 407

# To take input from the user
#num = int(input("Enter a number: "))

if num == 1:
    print(num, "is not a prime number")
elif num > 1:
   # check for factors
   for i in range(2,num):
       if (num % i) == 0:
           print(num,"is not a prime number")
           print(i,"times",num//i,"is",num)
           break
   else:
       print(num,"is a prime number")
       
# if input number is less than
# or equal to 1, it is not prime
else:
   print(num,"is not a prime number")

Output

407 is not a prime number
11 times 37 is 407

Here, we have used a for..else statement to check if num is prime.

It works on the logic that the else clause of the for loop runs if and only if we don't break out the for loop. That condition is met only when no factors are found, which means that the given number is prime.

So, in the else clause, we print that the number is prime.


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