# C++ Program to Add Two Distances (in inch-feet) System Using Structures

This program takes two distances (in inch-feet system), adds them and displays the result on the screen.

To understand this example, you should have the knowledge of the following C++ programming topics:

## Example: Add Distances Using Structures

``````#include <iostream>
using namespace std;

struct Distance {
int feet;
float inch;
}d1 , d2, sum;

int main() {
cout << "Enter 1st distance," << endl;
cout << "Enter feet: ";
cin >> d1.feet;
cout << "Enter inch: ";
cin >> d1.inch;

cout << "\nEnter information for 2nd distance" << endl;
cout << "Enter feet: ";
cin >> d2.feet;
cout << "Enter inch: ";
cin >> d2.inch;

sum.feet = d1.feet+d2.feet;
sum.inch = d1.inch+d2.inch;

// changing to feet if inch is greater than 12
if(sum.inch > 12) {
// extra feet
int extra = sum.inch / 12;

sum.feet += extra;
sum.inch -= (extra * 12);
}

cout << endl << "Sum of distances = " << sum.feet << " feet  " << sum.inch << " inches";
return 0;
}

``````

Output

```Enter 1st distance,
Enter feet: 6
Enter inch: 3.4

Enter information for 2nd distance
Enter feet: 5
Enter inch: 10.2

Sum of distances = 12 feet  1.6 inches
```

In this program, a structure `Distance` containing two data members (inch and feet) is declared to store the distance in the inch-feet system.

Here, two structure variables d1 and d2 are created to store the distance entered by the user. And, the sum variable stores the sum of the distances.

The `if` statement is used to convert inches to feet if the value of inch of sum variable is greater than `12`:

• The `int` variable extra stores the extra feet gained due to the value of inch being greater than `12`. This is obtained from the quotient of division between sum.inch and `12`.
• We then add the extra feet to sum.feet.
• The true value of sum.inch is then calculated by subtracting `extra * 12` from its initial value.