## Example: C++ Program to Reverse an Integer

```
#include <iostream>
using namespace std;
int main() {
int n, reversed_number = 0, remainder;
cout << "Enter an integer: ";
cin >> n;
while(n != 0) {
remainder = n % 10;
reversed_number = reversed_number * 10 + remainder;
n /= 10;
}
cout << "Reversed Number = " << reversed_number;
return 0;
}
```

**Output**

Enter an integer: 2345 Reversed number = 5432

This program takes an integer input from the user and stores it in variable `n`.

Then the while loop is iterated until `n != 0`

is false.

In each iteration, the remainder when the value of `n` is divided by **10** is calculated, `reversed_number` is computed and the value of `n` is decreased 10 fold.

Let us see this process in greater detail:

n | n != 0 | remainder | reversed_number |
---|---|---|---|

2345 | true | 5 | 0 * 10 + 5 = 5 |

234 | true | 4 | 5 * 10 + 4 = 54 |

23 | true | 3 | 54 * 10 + 3 = 543 |

2 | true | 2 | 543 * 10 + 2 = 5432 |

0 | false | - | Loop terminates. |

Finally, `reversed_number` (which contains the reversed number) is printed on the screen.