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C++ Program to Check Whether Number is Even or Odd

In this example, if...else statement is used to check whether a number entered by the user is even or odd.

To understand this example, you should have the knowledge of the following C++ programming topics:


Integers that are perfectly divisible by 2 are called even numbers.

And those integers that are not perfectly divisible by 2 are not known as odd numbers.

To check whether an integer is even or odd, the remainder is calculated when it is divided by 2 using modulus operator %. If the remainder is zero, that integer is even if not that integer is odd.


Example 1: Check Whether Number is Even or Odd using if else

#include <iostream>
using namespace std;

int main() {
  int n;

  cout << "Enter an integer: ";
  cin >> n;

  if ( n % 2 == 0)
    cout << n << " is even.";
  else
    cout << n << " is odd.";

  return 0;
}

Output

Enter an integer: 23
23 is odd.

In this program, an if..else statement is used to check whether n % 2 == 0 is true or not.

If this expression is true, n is even. Else, n is odd.

You can also use ternary operators ?: instead of if..else statement. The ternary operator is a shorthand notation of if...else statement.


Example 2: Check Whether Number is Even or Odd using ternary operators

#include <iostream>
using namespace std;

int main() {
  int n;

  cout << "Enter an integer: ";
  cin >> n;
    
  (n % 2 == 0) ? cout << n << " is even." :  cout << n << " is odd.";
    
  return 0;
}
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