Positive integers 1, 2, 3, 4... are known as natural numbers.
This program takes a positive integer from user( suppose user entered n ) then, this program displays the value of 1+2+3+....+n.
Example: Sum of Natural Numbers using loop
#include <iostream>
using namespace std;
int main() {
int n, sum = 0;
cout << "Enter a positive integer: ";
cin >> n;
for (int i = 1; i <= n; ++i) {
sum += i;
}
cout << "Sum = " << sum;
return 0;
}
Output
Enter a positive integer: 50 Sum = 1275
This program assumes that user always enters positive number.
If user enters negative number, Sum = 0 is displayed and program is terminated.
This program can also be done using recursion. Check out this article for calculating sum of natural numbers using recursion.