Example 1: Find Largest Among three numbers using if..else statement
public class Largest {
public static void main(String[] args) {
double n1 = -4.5, n2 = 3.9, n3 = 2.5;
if( n1 >= n2 && n1 >= n3)
System.out.println(n1 + " is the largest number.");
else if (n2 >= n1 && n2 >= n3)
System.out.println(n2 + " is the largest number.");
else
System.out.println(n3 + " is the largest number.");
}
}
Output
3.9 is the largest number.
In the above program, three numbers -4.5, 3.9 and 2.5 are stored in variables n1, n2 and n3 respectively.
Then, to find the largest, the following conditions are checked using if else statements
- If n1 is greater or equals to both n2 and n3, n1 is the greatest.
- If n2 is greater or equals to both n1 and n3, n2 is the greatest.
- Else, n3 is the greatest.
The greatest number can also be found using a nested if..else statement.
Example 2: Find the largest number among three using nested if..else statement
public class Largest {
public static void main(String[] args) {
double n1 = -4.5, n2 = 3.9, n3 = 5.5;
if(n1 >= n2) {
if(n1 >= n3)
System.out.println(n1 + " is the largest number.");
else
System.out.println(n3 + " is the largest number.");
} else {
if(n2 >= n3)
System.out.println(n2 + " is the largest number.");
else
System.out.println(n3 + " is the largest number.");
}
}
}
Output
5.5 is the largest number.
In the above program, instead of checking for two conditions in a single if statement, we use nested if to find the greatest.
Then, to find the largest, the following conditions are checked using if else statements
- If n1 is greater or equals to n2,
- and if n1 is greater or equals to n3, n1 is the greatest.
- else, n3 is the greatest.
- Else,
- if n2 is greater or equals to both n3, n2 is the greatest.
- else, n3 is the greatest.