Java Program to Find all Roots of a Quadratic Equation

To understand this example, you should have the knowledge of the following Java programming topics:


The standard form of a quadratic equation is:

ax2 + bx + c = 0

Here, a, b, and c are real numbers and a can't be equal to 0.

We can calculate the root of a quadratic by using the formula:

x = (-b ± √(b2-4ac)) / (2a)

The ± sign indicates that there will be two roots:

root1 = (-b + √(b2-4ac)) / (2a)
root1 = (-b - √(b2-4ac)) / (2a)

The term b2-4ac is known as the discriminant of a quadratic equation. It specifies the nature of roots. That is,

  • if discriminant > 0, roots are real and different
  • if discriminant == 0, roots are real and equal
  • if discriminant < 0, roots are complex and different

Example: Java Program to Find Roots of a Quadratic Equation

public class Main {

  public static void main(String[] args) {

    // value a, b, and c
    double a = 2.3, b = 4, c = 5.6;
    double root1, root2;

    // calculate the discriminant (b2 - 4ac)
    double discriminant = b * b - 4 * a * c;

    // check if discriminant is greater than 0
    if (discriminant > 0) {

      // two real and distinct roots
      root1 = (-b + Math.sqrt(discriminant)) / (2 * a);
      root2 = (-b - Math.sqrt(discriminant)) / (2 * a);

      System.out.format("root1 = %.2f and root2 = %.2f", root1, root2);
    }

    // check if discriminant is equal to 0
    else if (discriminant == 0) {

      // two real and equal roots
      // discriminant is equal to 0
      // so -b + 0 == -b
      root1 = root2 = -b / (2 * a);
      System.out.format("root1 = root2 = %.2f;", root1);
    }

    // if discriminant is less than zero
    else {

      // roots are complex number and distinct
      double real = -b / (2 * a);
      double imaginary = Math.sqrt(-discriminant) / (2 * a);
      System.out.format("root1 = %.2f+%.2fi", real, imaginary);
      System.out.format("\nroot2 = %.2f-%.2fi", real, imaginary);
    }
  }
}

Output

root1 = -0.87+1.30i and root2 = -0.87-1.30i

In the above program, the coefficients a, b, and c are set to 2.3, 4, and 5.6 respectively. Then, the discriminant is calculated as b2 - 4ac.

Based on the value of the discriminant, the roots are calculated as given in the formula above. Notice we've used library function Math.sqrt() to calculate the square root of a number.

We have used the format() method to print the calculated roots.

The format() function can also be replaced by printf() as:

System.out.printf("root1 = root2 = %.2f;", root1);

Before we wrap up, let’s put your knowledge of Java Program to Find all Roots of a Quadratic Equation to the test! Can you solve the following challenge?

Challenge:

Write a function to find the roots of a quadratic equation.

  • The formula to find the roots of a quadratic equation is: x = [-b ± sqrt(b^2 - 4ac)] / 2a.
  • Return the roots of a quadratic equation with coefficients a, b, and c as an array.
  • For example, if a = 1, b = -5 and c = 6, the expected output is {3, 2}.
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