In this program, you'll learn to display all armstrong numbers between two given intervals, low and high, in Kotlin.

A positive integer is called an Armstrong number of order `n` if

abcd... = a^{n}+ b^{n}+ c^{n}+ d^{n}+ ...

In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself. For example:

153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number.

This program is built on the concept of how to check whether an integer is an Armstrong number or not.

```
fun main(args: Array<String>) {
val low = 999
val high = 99999
for (number in low + 1..high - 1) {
var digits = 0
var result = 0
var originalNumber = number
// number of digits calculation
while (originalNumber != 0) {
originalNumber /= 10
++digits
}
originalNumber = number
// result contains sum of nth power of its digits
while (originalNumber != 0) {
val remainder = originalNumber % 10
result += Math.pow(remainder.toDouble(), digits.toDouble()).toInt()
originalNumber /= 10
}
if (result == number)
print("$number ")
}
}
```

When you run the program, the output will be:

1634 8208 9474 54748 92727 93084

In the above program, each number between the given interval high and low are checked.

After each check, number of `digits` and sum `result` are restored to 0.

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