Kotlin Program to Find the Largest Among Three Numbers

In this program, you'll learn to find the largest among three numbers using if else and when statement in Kotlin.

Example 1: Find Largest Among three numbers using if..else statement

fun main(args: Array<String>) {

val n1 = -4.5
val n2 = 3.9
val n3 = 2.5

if (n1 >= n2 && n1 >= n3)
println("\$n1 is the largest number.")
else if (n2 >= n1 && n2 >= n3)
println("\$n2 is the largest number.")
else
println("\$n3 is the largest number.")
}

When you run the program, the output will be:

3.9 is the largest number.

In the above program, three numbers -4.5, 3.9 and 2.5 are stored in variables n1, n2 and n3 respectively.

Then, to find the largest, the following conditions are checked using if else statements

• If n1 is greater or equals to both n2 and n3, n1 is the greatest.
• If n2 is greater or equals to both n1 and n3, n2 is the greatest.
• Else, n3 is the greatest.

The greatest number can also be found using a when statement.

Here's the equivalent Java code: Java Program to Find the Largest Among Three Numbers

Example 2: Find the largest number among three using when statement

fun main(args: Array<String>) {

val n1 = -4.5
val n2 = 3.9
val n3 = 5.5

when {
n1 >= n2 && n1 >= n3 -> println("\$n1 is the largest number.")
n2 >= n1 && n2 >= n3 -> println("\$n2 is the largest number.")
else -> println("\$n3 is the largest number.")
}
}

When you run the program, the output will be:

5.5 is the largest number.

In the above program, instead of using an if..else if..else block, we use when statement.

So, the above conditions in both the programs are the same.