In this program, you'll learn to reverse a number using a while loop in Kotlin.

```
fun main(args: Array<String>) {
var num = 1234
var reversed = 0
while (num != 0) {
val digit = num % 10
reversed = reversed * 10 + digit
num /= 10
}
println("Reversed Number: $reversed")
}
```

When you run the program, the output will be:

Reversed Number: 4321

In this program, while loop is used to reverse a number as given in the following steps:

- First, the remainder of
`num`divided by 10 is stored in the variable`digit`. Now,`digit`contains the last digit of`num`, i.e. 4.

`digit`is then added to the variable reversed after multiplying it by 10. Multiplication by 10 adds a new place in the reversed number. One-th place multiplied by 10 gives you tenth place, tenth gives you hundredth and so on. In this case,`reversed`contains 0 * 10 + 4 = 4.

`num`is then divided by 10 so that now it only contains first three digits: 123. - After second iteration,
`digit`equals 3,`reversed`equals 4 * 10 + 3 = 43 and`num`= 12 - After third iteration,
`digit`equals 2,`reversed`equals 43 * 10 + 2 = 432 and`num`= 1 - After fourth iteration,
`digit`equals 1,`reversed`equals 432 * 10 + 1 = 4321 and`num`= 0 - Now
`num`= 0, so the test expression`num != 0`

fails and while loop exits.`reversed`already contains the reversed number 4321.

Here's the equivalent Java code: Java Program to reverse a number

It takes a lot of effort and cost to maintain Programiz. We would be grateful if you support us by either:

**Disabling AdBlock on Programiz. We do not use intrusive ads.**

or

Donate on Paypal
By using Programiz, you agree to use cookies as stated in our Privacy policy Continue