Python Program to Find Armstrong Number in an Interval

Example to find all Armstrong numbers between two integers. To solve this problem, we have used nested loop and if statement.

To understand this example, you should have the knowledge of following Python programming topics:

A positive integer is called an Armstrong number of order n if

abcd... = an + bn + cn + dn + ...

For example,

153 = 1*1*1 + 5*5*5 + 3*3*3  // 153 is an Armstrong number.

Visit this page to learn how you can check whether a number is an Armstrong number or not in Python.

Source Code

# Program to check Armstrong numbers in certain interval

lower = 100
upper = 2000

# To take input from the user
# lower = int(input("Enter lower range: "))
# upper = int(input("Enter upper range: "))

for num in range(lower, upper + 1):

   # order of number
   order = len(str(num))
   # initialize sum
   sum = 0

   # find the sum of the cube of each digit
   temp = num
   while temp > 0:
       digit = temp % 10
       sum += digit ** order
       temp //= 10

   if num == sum:



Here, we have set the lower limit 100 in variable lower and upper limit 2000 in variable upper. We have used for loop to iterate from variable lower to upper. In iteration, the value of lower is increased by 1 and checked whether it is an Armstrong number or not.

You can change the range and test out by changing the variables lower and upper. Note, the variable lower should be lower than upper for this program to work properly.