Example to find all factors of an integer (entered by the user) using for loop and if statement.

To understand this example, you should have the knowledge of following C++ programming topics:

This program takes a positive integer from an user and displays all the factors of that number.

```
#include <iostream>
using namespace std;
int main()
{
int n, i;
cout << "Enter a positive integer: ";
cin >> n;
cout << "Factors of " << n << " are: " << endl;
for(i = 1; i <= n; ++i)
{
if(n % i == 0)
cout << i << endl;
}
return 0;
}
```

**Output**

Enter a positive integer: 60 Factors of 60 are: 1 2 3 4 5 6 12 15 20 30 60

In this program, an integer entered by user is stored in variable `n`.

Then, for loop is executed with an initial condition `i = 1`

and checked whether `n` is perfectly divisible by `i` or not. If `n` is perfectly divisible by `i` then, `i` will be the factor of `n`.

In each iteration, the value of `i` is updated (increased by 1).

This process goes until test condition `i <= n`

becomes false,i.e., this program checks whether number entered by user `n ` is perfectly divisible by all numbers from 1 to `n` and all displays factors of that number.

It takes a lot of effort and cost to maintain Programiz. We would be grateful if you support us by either:

**Disabling AdBlock on Programiz. We do not use intrusive ads.**

or

Donate on Paypal