The standard form of a quadratic equation is:

ax^{2}+ bx + c = 0, where a, b and c are real numbers and a ≠ 0

The solutions of this quadratic equation is given by:

(-b ± (b ** 2 - 4 * a * c) ** 0.5) / (2 * a)

## Source Code

```
# Solve the quadratic equation ax**2 + bx + c = 0
# import complex math module
import cmath
a = 1
b = 5
c = 6
# calculate the discriminant
d = (b**2) - (4*a*c)
# find two solutions
sol1 = (-b-cmath.sqrt(d))/(2*a)
sol2 = (-b+cmath.sqrt(d))/(2*a)
print('The solution are {0} and {1}'.format(sol1,sol2))
```

**Output**

Enter a: 1 Enter b: 5 Enter c: 6 The solutions are (-3+0j) and (-2+0j)

We have imported the `cmath`

module to perform complex square root. First, we calculate the discriminant and then find the two solutions of the quadratic equation.

You can change the value of `a`, `b` and `c` in the above program and test this program.

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