The standard form of a quadratic equation is:
ax2 + bx + c = 0, where a, b and c are real numbers and a ≠ 0
The solutions of this quadratic equation is given by:
(-b ± (b ** 2 - 4 * a * c) ** 0.5) / (2 * a)
Source Code
# Solve the quadratic equation ax**2 + bx + c = 0
# import complex math module
import cmath
a = 1
b = 5
c = 6
# calculate the discriminant
d = (b**2) - (4*a*c)
# find two solutions
sol1 = (-b-cmath.sqrt(d))/(2*a)
sol2 = (-b+cmath.sqrt(d))/(2*a)
print('The solution are {0} and {1}'.format(sol1,sol2))
Output
Enter a: 1 Enter b: 5 Enter c: 6 The solutions are (-3+0j) and (-2+0j)
We have imported the cmath module to perform complex square root. First, we calculate the discriminant and then find the two solutions of the quadratic equation.
You can change the value of a, b and c in the above program and test this program.
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