 # Python Program to Transpose a Matrix

To understand this example, you should have the knowledge of the following Python programming topics:

In Python, we can implement a matrix as a nested list (list inside a list). We can treat each element as a row of the matrix.

For example `X = [[1, 2], [4, 5], [3, 6]]` would represent a 3x2 matrix. The first row can be selected as `X`. And, the element in the first-row first column can be selected as `X`.

Transpose of a matrix is the interchanging of rows and columns. It is denoted as X'. The element at ith row and jth column in X will be placed at jth row and ith column in X'. So if X is a 3x2 matrix, X' will be a 2x3 matrix.

Here are a couple of ways to accomplish this in Python.

## Matrix Transpose using Nested Loop

``````# Program to transpose a matrix using a nested loop

X = [[12,7],
[4 ,5],
[3 ,8]]

result = [[0,0,0],
[0,0,0]]

# iterate through rows
for i in range(len(X)):
# iterate through columns
for j in range(len(X)):
result[j][i] = X[i][j]

for r in result:
print(r)
``````

Output

```[12, 4, 3]
[7, 5, 8]
```

In this program, we have used nested `for` loops to iterate through each row and each column. At each point we place the X[i][j] element into result[j][i].

## Matrix Transpose using Nested List Comprehension

``````''' Program to transpose a matrix using list comprehension'''

X = [[12,7],
[4 ,5],
[3 ,8]]

result = [[X[j][i] for j in range(len(X))] for i in range(len(X))]

for r in result:
print(r)``````

The output of this program is the same as above. We have used nested list comprehension to iterate through each element in the matrix.