 # Java Program to Count Number of Digits in an Integer

To understand this example, you should have the knowledge of the following Java programming topics:

## Example 1: Count Number of Digits in an Integer using while loop

``````public class Main {

public static void main(String[] args) {

int count = 0, num = 0003452;

while (num != 0) {
// num = num/10
num /= 10;
++count;
}

System.out.println("Number of digits: " + count);
}
}``````

Output

`Number of digits: 4`

In this program, `while` the loop is iterated until the test expression `num != 0` is evaluated to 0 (false).

• After the first iteration, num will be divided by 10 and its value will be 345. Then, the count is incremented to 1.
• After the second iteration, the value of num will be 34 and the count is incremented to 2.
• After the third iteration, the value of num will be 3 and the count is incremented to 3.
• After the fourth iteration, the value of num will be 0 and the count is incremented to 4.
• Then the test expression is evaluated to false and the loop terminates.

Note: The program ignores any zero's present before the number. Hence, for digits like 000333, the output will be 3.

## Example 2: Count Number of Digits in an Integer using for loop

``````public class Main {

public static void main(String[] args) {

int count = 0, num = 123456;

for (; num != 0; num /= 10, ++count) {
}

System.out.println("Number of digits: " + count);
}
}``````

Output

`Number of digits: 6`

In this program, instead of using a while loop, we use a for loop without any body.

On each iteration, the value of num is divided by 10 and count is incremented by 1.

The `for` loop exits when `num != 0` is false, i.e. num = 0.

Since, `for` loop doesn't have a body, you can change it to a single statement in Java as such:

`for(; num != 0; num/=10, ++count);`