Java Program to Display Armstrong Numbers Between Intervals Using Function

To understand this example, you should have the knowledge of the following Java programming topics:

To find all Armstrong numbers between two integers, `checkArmstrong()` function is created. This function checks whether a number is Armstrong or not.

Example: Armstrong Numbers Between Two Integers

``````public class Armstrong {

public static void main(String[] args) {

int low = 999, high = 99999;

for(int number = low + 1; number < high; ++number) {

if (checkArmstrong(number))
System.out.print(number + " ");
}
}

public static boolean checkArmstrong(int num) {
int digits = 0;
int result = 0;
int originalNumber = num;

// number of digits calculation
while (originalNumber != 0) {
originalNumber /= 10;
++digits;
}

originalNumber = num;

// result contains sum of nth power of its digits
while (originalNumber != 0) {
int remainder = originalNumber % 10;
result += Math.pow(remainder, digits);
originalNumber /= 10;
}

if (result == num)
return true;

return false;
}
}``````

Output

`1634 8208 9474 54748 92727 93084 `

In the above program, we've created a function named `checkArmstrong()` which takes a parameter num and returns a boolean value.

If the number is Armstrong, it returns `true`. If not, it returns `false`.

Based on the return value, the number is printed on the screen inside `main()` function.